Determine The Smallest 3 Digit Number Which Is Exactly Divisible By 6 We have to find the smallest $$3$$ digit multiple of $$24$$. it can be seen that $$24\times 4=96$$ and $$24\times 5=120$$. hence, the smallest $$3$$ digit number which is exactly divisible by $$6, 8$$ and $$12$$ is $$120$$. Now we will divide the smallest 3 digit number with the lcm obtained, and the remainder will be subtracted from the dividend, and 24 will be added to it to make it perfectly divisible. ∴ 100 24 = 4, remainder = 4. according to the above statement. = (100 – 4) 24 = 96 24 = 120. hence, the smallest 3 digit number which is exactly.
Determine The Smallest 3 Digit Number Which Is Exactly Divisible By 6 Hence, the smallest 3 digit number which is exactly divisible by 6, 8 and 12 is 120. this is the required answer. note: in such types of questions it is always advisable to divide the final number by the given numbers to ensure that they are divisible by the final answer. so, 120 6 = 20l 120 8 = 15 120 12 = 10 120 6 = 20 l 120 8 = 15 120 12 = 10. We know that the smallest 3 digit number is 100. let's find the lcm of 6, 8, and 12 as shown below. as we can observe from the division method, lcm of 6, 8, and 12 is 2 × 2 × 2 × 3 = 24. thus, all the multiples of 24 will also be divisible by 6, 8, and 12. now we will divide the smallest 3 digit number with the lcm obtained, and the. A number is divisible by 7 if and only if subtracting nine times the last digit from the rest gives a number divisible by 7. yet another alternative rule for divisibility by 7. a number is divisible by 7 if and only if the alternating sum of blocks of three digits from right to left is divisible by 7. To determine the smallest 3 digit number that is exactly divisible by 6, 8, and 12, we need to find the least common multiple (lcm) of those numbers, since the lcm will be the smallest number that all of them divide into without leaving a remainder. first, we find the prime factorization of each number: 6 = 2 x 3. 8 = 2^3. 12 = 2^2 x3.
Determine The Smallest 3 Digit Number Which Is Exactly Divisible By 6 A number is divisible by 7 if and only if subtracting nine times the last digit from the rest gives a number divisible by 7. yet another alternative rule for divisibility by 7. a number is divisible by 7 if and only if the alternating sum of blocks of three digits from right to left is divisible by 7. To determine the smallest 3 digit number that is exactly divisible by 6, 8, and 12, we need to find the least common multiple (lcm) of those numbers, since the lcm will be the smallest number that all of them divide into without leaving a remainder. first, we find the prime factorization of each number: 6 = 2 x 3. 8 = 2^3. 12 = 2^2 x3. To determine the smallest 3 digit number that is exactly divisible by 6, 8, and 12, we need to find the least common multiple (lcm) of these numbers. lcm is the smallest number that is divisible by all the given numbers. in this case, we have 6, 8, and 12. we can write the prime factorization of each number as: 6 = 2 x 3, 8 = 2 x 2 x 2, and 12. To determine the smallest 3 digit number which is exactly divisible by 6, 8, and 12, we need to find the least common multiple (lcm) of these numbers. the lcm of 6, 8, and 12 is 24. from the set of 3 digit numbers, the smallest one that is a multiple of 24 is 120.
Determine The Smallest 3 Digit Number Which Is Exactly Divisible By 6 To determine the smallest 3 digit number that is exactly divisible by 6, 8, and 12, we need to find the least common multiple (lcm) of these numbers. lcm is the smallest number that is divisible by all the given numbers. in this case, we have 6, 8, and 12. we can write the prime factorization of each number as: 6 = 2 x 3, 8 = 2 x 2 x 2, and 12. To determine the smallest 3 digit number which is exactly divisible by 6, 8, and 12, we need to find the least common multiple (lcm) of these numbers. the lcm of 6, 8, and 12 is 24. from the set of 3 digit numbers, the smallest one that is a multiple of 24 is 120.
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