Find The Least Square Number Which Is Exactly Divisible By Each One Find the least square number exactly divisible by each one is equal to the number 6, 9, 15 and 20. view solution. click here:point up 2:to get an answer to your question :writing hand:find the least square number which is exactly divisible by each of the numbers 81215. Q. find the least square number , exactly divisible by each one of the numbers: (i) 6,9,15 and 20 (ii) 8,12,15 and 20. q. find the least perfect square which is exactly divisible by each of the numbers 6, 9, 15 and 20. [4 marks] q. the least square number which is exactly divisible by each of these number 6,9,15 and 20 is.
Find The Least Square Number Exactly Divisible By Each One Of Th The least square number which is exactly divisible by 8, 9, and 10 = l.c.m. of 8, 9, and 10. hence,l.c.m = $$2 \times 2 \times 2 \times 3 \times 3 \times 5 = 360$$ as we calculate, $$2 \times 2 \times 2 \times 3 \times 3 \times 5$$ 2 and 5 have incomplete pairs. Solution: we have to find the smallest square divisible by 8, 9 and 10. the least number divisible by 8, 9 and 10 is their lcm. on finding the lcm of 8, 9 and 10, now, lcm of 8, 9 and 10 = 2 × 2 × 2 × 3 × 3 × 5 = 360. we observe that 2 and 5 do not occur in pairs. so, 360 is not a perfect square. now, 360 must be multiplied by 2 × 5 to. Step 2: find the least square no divisible by given numbers. on grouping the factors of 360, we get . 360 = (2 × 2) × 2 × (3 × 3) × 5. that is 2 and 5 is not able to make their pair. so, to make it perfect square, 360 must be multiplied with 2 × 5 = 10. ∴ 360 × 10 = 3600. hence, 3600 is the smallest square number divisible by each one. Given: the least square number which is exactly divisible by 8, 9 and 10 is equal to l.c.m. of 8, 9 and 10.
Find The Least Square Number Exactly Divisible By Each One Of Th Step 2: find the least square no divisible by given numbers. on grouping the factors of 360, we get . 360 = (2 × 2) × 2 × (3 × 3) × 5. that is 2 and 5 is not able to make their pair. so, to make it perfect square, 360 must be multiplied with 2 × 5 = 10. ∴ 360 × 10 = 3600. hence, 3600 is the smallest square number divisible by each one. Given: the least square number which is exactly divisible by 8, 9 and 10 is equal to l.c.m. of 8, 9 and 10. The number that will be perfectly divisible by each of the numbers 4, 9 and 10 will be their lcm. lcm of 4, 9, 10. = 2 × 2 × 3 × 3 × 5. = 180. here, the prime factor 5 does not have a pair. therefore 180 is multiplied by 5 then the number obtained is a perfect square. thus, 180 × 5 = 900. Transcript. ex 5.3, 10 find the smallest square number that is divisible by each of the numbers 8, 15 and 20.smallest square number divisible by 8, 15, 20 = l.c.m of 8, 15, 20 or multiple of l.c.m finding l.c.m of 8, 15, 20 l.c.m of 8, 15, 20 = 2 × 2 × 2 × 3 × 5 = 4 × 6 × 5 = 4 × 30 = 120 checking if 120 is a perfect square we see that, 120 = 2 × 2 × 2 × 3 × 5 here, 2, 3 & 5 do not.
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