Find The Least Number Of Five Digits Which When Divided By 12 16 21 36 And 40 Leaves In Each

Find The Least Number Of Five Digits Which When Divided By 12 For more questions subscribe our channel: c gravitycoachingcentre?sub confirmation=1". Numbers = 12, 16, 40. the remainder in each case = 8. concept used: lowest common multiple. calculation: ⇒ least five digit number = 10,000. ⇒ now, taking lcm of 12, 16 and 40, ⇒ 12 = 2 × 2 × 3. ⇒ 16 = 2 × 2 × 2 × 2. ⇒ 40 = 2 × 2 × 2 × 5. ⇒ lcm = 2 × 2 × 2 × 2 × 3 × 5 = 240. now, we divide 10,000 by 240 and we get the.

Find The Least Number Of Five Digits Which When Divided By 12 Least number when divided by 12, 16, 24, 36 and leaves find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when. Find the least number of five digits which when divided by 12, 16, 21, 36 and 40 leaves in each case a 35151082. Find the sum of a least six digits number, which when divided by 4, 6, 10 and 15 leaves the remainder of 2 in each case. The least number of five digits which is exactly divisible by each of 8, 12, 18, 40 and 45 is multiple of l c m of these numbers. the least number of five digits which is exactly divisible by each of. 8. ,.

Find The Least Number Which When Divided By 16 36 And 40 о Find the sum of a least six digits number, which when divided by 4, 6, 10 and 15 leaves the remainder of 2 in each case. The least number of five digits which is exactly divisible by each of 8, 12, 18, 40 and 45 is multiple of l c m of these numbers. the least number of five digits which is exactly divisible by each of. 8. ,. Find the largest number of five digits which , when divided by 16, 24, 30 or 36, leaves the same remainder 10 in each case. view solution find the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case. L.c.m. of 12, 16, 24, 36 = 2 × 2 × 2 × 3 × 3 × 5 = 360 360 is the least number which when divided by the given numbers will leave remainder 0 in each case. therefore, the least number which when divided by 12, 15, 18 and 24 leaves a remainder 5 in each case = 360 5 = 365.

Find The Least Number Of Five Digits That Is Exactly Divisible By 1 Find the largest number of five digits which , when divided by 16, 24, 30 or 36, leaves the same remainder 10 in each case. view solution find the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case. L.c.m. of 12, 16, 24, 36 = 2 × 2 × 2 × 3 × 3 × 5 = 360 360 is the least number which when divided by the given numbers will leave remainder 0 in each case. therefore, the least number which when divided by 12, 15, 18 and 24 leaves a remainder 5 in each case = 360 5 = 365.

Example 14 Find Least Number Which When Divided By 12 16 24 And