Find The Least Square Number Exactly Divisible By Each One Of The

find The Least Square Number Exactly Divisible By Each One Of The
find The Least Square Number Exactly Divisible By Each One Of The

Find The Least Square Number Exactly Divisible By Each One Of The The least square number which is exactly divisible by 8, 9, and 10 = l.c.m. of 8, 9, and 10. hence,l.c.m = $$2 \times 2 \times 2 \times 3 \times 3 \times 5 = 360$$ as we calculate, $$2 \times 2 \times 2 \times 3 \times 3 \times 5$$ 2 and 5 have incomplete pairs. Find the least square number exactly divisible by each one is equal to the number 6, 9, 15 and 20. view solution. click here:point up 2:to get an answer to your question :writing hand:find the least square number which is exactly divisible by each of the numbers 81215.

find The Least Square Number Exactly Divisible By Each One Of The
find The Least Square Number Exactly Divisible By Each One Of The

Find The Least Square Number Exactly Divisible By Each One Of The Find the smallest square number that is divisible by each of the numbers 4, 9, and 10. find the smallest number by which the given number must be divided so that the resulting number is a perfect square: 2904. by just examining the unit digit, can you tell which of the following cannot be whole square? 1023. Q. find the least square number , exactly divisible by each one of the numbers: (i) 6,9,15 and 20 (ii) 8,12,15 and 20. q. find the least perfect square which is exactly divisible by each of the numbers 6, 9, 15 and 20. [4 marks] q. the least square number which is exactly divisible by each of these number 6,9,15 and 20 is. To make it perfect square we need to multiply it by 5 = 2 2 × 3 2 × 5 2 = 30 2 = 900 ∴ 900 is the least square number which is exactly divisible by each of the numbers 6 , 9 , 15 and 20 was this answer helpful?. Find the least number which is exactly divisible by 10, 15, 20 and also a perfect square. find the least number divisible by 15, 20, 24, 32, and 36. find the least square number which is exactly divisible by 8, 9 and 10; find the smallest square number that is divisible by each of the numbers 5, 15 and 45.

find The Least Square Number Exactly Divisible By Each One Of The The
find The Least Square Number Exactly Divisible By Each One Of The The

Find The Least Square Number Exactly Divisible By Each One Of The The To make it perfect square we need to multiply it by 5 = 2 2 × 3 2 × 5 2 = 30 2 = 900 ∴ 900 is the least square number which is exactly divisible by each of the numbers 6 , 9 , 15 and 20 was this answer helpful?. Find the least number which is exactly divisible by 10, 15, 20 and also a perfect square. find the least number divisible by 15, 20, 24, 32, and 36. find the least square number which is exactly divisible by 8, 9 and 10; find the smallest square number that is divisible by each of the numbers 5, 15 and 45. Step 2: find the least square no divisible by given numbers. on grouping the factors of 360, we get . 360 = (2 × 2) × 2 × (3 × 3) × 5. that is 2 and 5 is not able to make their pair. so, to make it perfect square, 360 must be multiplied with 2 × 5 = 10. ∴ 360 × 10 = 3600. hence, 3600 is the smallest square number divisible by each one. Solution: we have to find the smallest square divisible by 8, 9 and 10. the least number divisible by 8, 9 and 10 is their lcm. on finding the lcm of 8, 9 and 10, now, lcm of 8, 9 and 10 = 2 × 2 × 2 × 3 × 3 × 5 = 360. we observe that 2 and 5 do not occur in pairs. so, 360 is not a perfect square. now, 360 must be multiplied by 2 × 5 to.

find The Least Square Number Exactly Divisible By Each One Of The
find The Least Square Number Exactly Divisible By Each One Of The

Find The Least Square Number Exactly Divisible By Each One Of The Step 2: find the least square no divisible by given numbers. on grouping the factors of 360, we get . 360 = (2 × 2) × 2 × (3 × 3) × 5. that is 2 and 5 is not able to make their pair. so, to make it perfect square, 360 must be multiplied with 2 × 5 = 10. ∴ 360 × 10 = 3600. hence, 3600 is the smallest square number divisible by each one. Solution: we have to find the smallest square divisible by 8, 9 and 10. the least number divisible by 8, 9 and 10 is their lcm. on finding the lcm of 8, 9 and 10, now, lcm of 8, 9 and 10 = 2 × 2 × 2 × 3 × 3 × 5 = 360. we observe that 2 and 5 do not occur in pairs. so, 360 is not a perfect square. now, 360 must be multiplied by 2 × 5 to.

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